Sacu
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(Redirected from Tincova)
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Sacu | |
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Commune | |
Location in Caraș-Severin County Location in Caraș-Severin County |
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Location in Romania | |
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Country | ![]() |
County | Caraş-Severin County |
Population (2002)[1] | |
• Total | 1,681 |
Time zone | EET (UTC+2) |
• Summer (DST) | EEST (UTC+3) |
Sacu (Hungarian: Szákul) is a commune in Caraş-Severin County, western Romania with a population of 1681 people. It is composed of three villages: Sacu, Sălbăgelu Nou (Gyulatelep) and Tincova (Tinkova).
References
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- ↑ (Romanian) "Sacu", at the Erdélyi Magyar Adatbank's Recensământ 2002; Retrieved on August 22, 2009