2019 Grand Prix SAR La Princesse Lalla Meryem – Doubles
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Doubles | |
---|---|
2019 Grand Prix SAR La Princesse Lalla Meryem | |
Champions | ![]() ![]() |
Runners-up | ![]() ![]() |
Final score | 7–5, 6–1 |
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Anna Blinkova and Raluca Olaru were the defending champions,[1] but chose not to participate this year.
María José Martínez Sánchez and Sara Sorribes Tormo won the title, defeating Georgina García Pérez and Oksana Kalashnikova in the final, 7–5, 6–1.
Contents
Seeds
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María José Martínez Sánchez /
Sara Sorribes Tormo (champions)
Alexandra Panova /
Vera Zvonareva (first round)
Monique Adamczak /
Jessica Moore (first round)
Alexa Guarachi /
Sabrina Santamaria (semifinals)
Draw
Key
|
|
Draw
First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | ![]() ![]() |
6 | 6 | ||||||||||||||||||||||||
![]() ![]() |
4 | 4 | 1 | ![]() ![]() |
6 | 77 | |||||||||||||||||||||
![]() ![]() |
6 | 6 | ![]() ![]() |
1 | 62 | ||||||||||||||||||||||
WC | ![]() ![]() |
2 | 3 | 1 | ![]() ![]() |
6 | 6 | ||||||||||||||||||||
4 | ![]() ![]() |
4 | 6 | [10] | 4 | ![]() ![]() |
3 | 1 | |||||||||||||||||||
![]() ![]() |
6 | 3 | [8] | 4 | ![]() ![]() |
6 | 3 | [10] | |||||||||||||||||||
![]() ![]() |
6 | 6 | ![]() ![]() |
3 | 6 | [4] | |||||||||||||||||||||
![]() ![]() |
4 | 1 | 1 | ![]() ![]() |
7 | 6 | |||||||||||||||||||||
WC | ![]() ![]() |
7 | 63 | [10] | ![]() ![]() |
5 | 1 | ||||||||||||||||||||
![]() ![]() |
5 | 77 | [2] | WC | ![]() ![]() |
w/o | |||||||||||||||||||||
![]() ![]() |
6 | 6 | ![]() ![]() |
||||||||||||||||||||||||
3 | ![]() ![]() |
2 | 3 | WC | ![]() ![]() |
63 | 3 | ||||||||||||||||||||
![]() ![]() |
6 | 6 | ![]() ![]() |
77 | 6 | ||||||||||||||||||||||
![]() ![]() |
2 | 2 | ![]() ![]() |
6 | 6 | ||||||||||||||||||||||
![]() ![]() |
5 | 6 | [10] | ![]() ![]() |
0 | 2 | |||||||||||||||||||||
2 | ![]() ![]() |
7 | 3 | [5] |
References
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External Links
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