Oak Grove Township, Benton County, Indiana

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Oak Grove Township
Township
Location of Oak Grove Township in Benton County
Location of Oak Grove Township in Benton County
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Country United States
State Indiana
County Benton
Organized July 1840
Government
 • Type Indiana township
Area
 • Total 35.53 sq mi (92.0 km2)
 • Land 35.51 sq mi (92.0 km2)
 • Water 0.02 sq mi (0.05 km2)
Elevation[1] 748 ft (228 m)
Population (2010)
 • Total 1,581
 • Density 44.5/sq mi (17.2/km2)
Time zone EST (UTC-5)
 • Summer (DST) EDT (UTC-4)
FIPS code 18-55620[2]
GNIS feature ID 453681

Oak Grove Township is one of eleven townships in Benton County, Indiana. As of the 2010 census, its population was 1,581 and it contained 705 housing units.[3] It was one of the first three townships originally created by the county's commissioners in 1840.[4] It takes its name from White Oak Grove which grew southwest of Oxford.[5]

Geography

According to the 2010 census, the township has a total area of 35.53 square miles (92.0 km2), of which 35.51 square miles (92.0 km2) (or 99.94%) is land and 0.02 square miles (0.052 km2) (or 0.06%) is water.[3]

Cities and towns

Unincorporated towns

Adjacent townships

Major highways

Cemeteries

The township contains two cemeteries: Justus and Oxford.

References

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External links