United States presidential election in Maine, 1992
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The 1992 United States presidential election in Maine took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Maine was won by Governor Bill Clinton (D-Arkansas) with 38.77% of the popular vote over businessman Ross Perot (I-Texas) with 30.44%. Incumbent President George H. W. Bush (R-Texas) finished in third, close behind Perot, with 30.39% of the popular vote.[1] Despite the Bush family having ties to Maine, Perot beat Bush for second place in the state by a slim margin of 316 votes, making Maine one of two states where Perot finished better than third place, the other being Utah.[2] Clinton ultimately won the national vote, defeating both incumbent President Bush and Perot.[3]
Results
United States presidential election in Maine, 1992[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Bill Clinton | 263,420 | 38.77% | 4 | |
Independent | Ross Perot | 206,820 | 30.44% | 0 | |
Republican | George H. W. Bush | 206,504 | 30.39% | 0 | |
Libertarian | Andre Marrou | 1,681 | 0.25% | 0 | |
New Alliance | Lenora Fulani | 519 | 0.08% | 0 | |
U.S. Taxpayers' | Howard Phillips | 464 | 0.07% | 0 | |
Write-ins | 91 | 0.01% | 0 | ||
Totals | 679,499 | 100.0% | 4 | ||
Voter Turnout (Voting age/Registered) | 72%/70% |
References
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